3.2.4 Exact solution for the Metal-Semiconductor Junction
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3.1.2 Exact solution of the M-S junction
In order to correctly asses the error made when using the full
depletion approximation we now derive the correct solution by solving
Poisson's equation analytically. The actual solution for the
potential is then obtained by numerically integrating the expression
for the electric field. We start from the charge density
r in a semiconductor for the general case
where electrons, holes, ionized acceptors and ionized donors are
present:
[3.1.7]
Where f is the potential in the
semiconductor. The potential is chosen to equal zero deep into the
semiconductor. For an n-type semiconductor without acceptors or free
holes this can be further reduced to:
[3.1.8]
assuming the semiconductor to be non-degenerate and fully ionized. A
similar expression can be obtained for p-type material. Poisson's
law can then be rewritten as:
[3.1.9]
Multiplying both sides with df/dx, this
equation can be integrated between an arbitrary point x and infinity.
The electric field at infinity (deep in the semiconductor) is taken
to be zero. The electric field for a given potential is then:
[3.1.10]
Where the sign function equals +1 or -1 depending
on the sign of f and LD is
the
Debye length given by,
Equation [3.1.10]
is plotted in figure 3.2 using normalized parameters. Depletion
occurs for negative potentials while accumulation occurs for
positive potentials.
Fig.3.2 Absolute value of the normalized electric field, |E| LD/Vt, versus normalized potential, f/Vt
Applying Gauss's law (Q = esE) we the find the relation between the total charge in the semiconductor region and the total potential
across the semiconductor. The capacitance can also be obtained from:
[3.1.11]
where fs is the potential
across the semiconductor and equals -f
i + Va. This expression can be approximated
for fs< 0 and
|fs| >> Vt
yielding:
[3.1.12]
This expression equals [3.1.6] as derived using the full depletion
approximation, except for the added term, Vt, in the denominator.
This expression yields the capacitance value with a relative accuracy better
than 0.3 % for Va < f
i - 6Vt.
3.1.2 Numeric solution
A numeric solution can be obtained by integrating equation [3.1.10]. The
solution to the energy band diagram, the charge density, the electric field
and the potential are shown in the figures below: Integration was started
four Debye lengths to the right of the edge of the depletion region as
obtained using the full depletion approximation. Initial conditions were
obtained by assuming the potential at the starting point to be adequately
expressed by a solution to the homogenous equation:
[3.1.13]
Shown are solutions for a gold-silicon M-S junction with F
M = 4.75V, c = 4.05V, N
d = 1016 cm-3 and
es/e
0 = 11.9.
Fig.3.3 Energy band diagram of an M-S junction
Fig.3.4 Charge density versus position in a M-S junction. The
solid line is the numeric solution, and the dotted line is the solution
based on the full depletion approximation.

Fig.3.5 Electric field versus distance in a M-S junction. The solid
line is the numeric solution, and the dotted line is the solution based on
the full depletion approximation.
Fig.3.6 Potential versus distance of an M-S junction. The solid line
is the numeric solution, and the dotted line is the solution based on the
full depletion approximation.
a) Depletion at the Metal-Semiconductor interface
Most metal semiconductor contacts have a depletion region adjacent to the
interface. We distinguish between the case where a large potential variation
is found across the semiconductor, for which only a small correction is
obtained compared to the full depletion approximation, and the case where a
small potential variation exists across the semiconductor, for which the full
depletion approximation does not apply.
Large potential approximation
If the potential difference across the semiconductor is larger than the
thermal voltage, or fs =
Va - fi < 0 and
|Va - fi| >> kT/q
we find the effective depletion layer width, xd, defined as the
ratio of the total depletion layer charge to the charge density of the fully
ionized donors, to be:
[3.1.14]
where LD is the extrinsic Debye length of the semiconductor,
which is given by:
[3.1.15]
The small signal capacitance can be expressed by:
[3.1.16]
where Qd is the total charge per unit area in the depletion
layer. This result differs from the one obtained by using the full depletion
approximation in that the applied voltage is increased by the thermal
voltage. However the capacitance is still the ratio of the dielectric
constant to the depletion layer width.
Small potential approximation
If the potential difference across the semiconductor is smaller than the
thermal voltage, or f = Va -
fi < 0 and |Va -
fi| < kT/q, the depletion layer
width is proportional to the Debye length and the applied voltage:
[3.1.17]
and the capacitance is constant, independent of the applied voltage:
[3.1.18]
b) Accumulation at the Metal-Semiconductor interface
Accumulation occurs at the semiconductor metal interface if the Fermi
level of the metal lies between the conduction band edge and the Fermi
level in the n-type semiconductor, or Fs >
FM > c .
A similar condition can be defined for p-type material. Equation [3.1.10]
applies for depletion as well as accumulation. However it does not provide
a solution for the electric field and potential as a function of position.
Instead we start again from the integral formulation of equation [3.1.10]
but set the potential equal to zero at the interface and integrate from 0
to x. We also assume that the electron concentration at the surface, ns is
much larger than the donor concentration. Using this convention, equation [3.1.10]
can be rewritten as:
[3.1.19]
integrating this equation again from 0 to x yields:
[3.1.20]
from which the charge density can be obtained:
[3.1.21]
Integration of the charge density yields the electric field.
[3.1.22]
The width of the accumulation layer is obtained by solving the expression
for the potential for x with f(xd) =
fi - Va .
[3.1.23]
The correct solution can also be obtained by integrating [3.1.10].
A solution for a M-S junction with FM
= 4.2V, c = 4.05V, Nd =
1016 cm-3 and
es/e
0 = 11.9 is shown in the figures below.
Fig.3.7 Charge density, electric field, potential and energy band
diagram under accumulation conditions.
3.2.3
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© Bart Van Zeghbroeck 1997